temukan nilai x dari
[tex] {8}^{x + 1 } \: = \: {16}^{4x + 18} = [/tex]
mohon bantuannya![]()
[tex] {8}^{x + 1 } \: = \: {16}^{4x + 18} = [/tex]
mohon bantuannya
Penjelasan dengan langkah-langkah:
[tex] {8}^{x + 1} = {16}^{4x + 18} \\ {2}^{3(x + 1)} = {2}^{4(4x + 18)} \\ {2}^{3x + 3} = {2}^{16x + 72} \\ 3x + 3 = 16x + 72 \\ 3x - 16x = 72 - 3 \\ - 13x = 69 \\ x = - \frac{69}{13} [/tex]
Semoga membantu....
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